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12991362593472 = 26361730615351
BaseRepresentation
bin1011110100001100100110…
…0011010111001011000000
31200222221222101200211000000
42331003021203113023000
53200322302310442342
643344052151000000
72510411035015224
oct275031143271300
950887871624000
1012991362593472
11415967355539a
121559991069000
13733107380493
1432cadcc38784
15177e0623044c
hexbd0c98d72c0

12991362593472 has 392 divisors, whose sum is σ = 40946584270752. Its totient is φ = 4073628672000.

The previous prime is 12991362593333. The next prime is 12991362593497. The reversal of 12991362593472 is 27439526319921.

12991362593472 is a `hidden beast` number, since 1 + 2 + 9 + 9 + 1 + 36 + 2 + 593 + 4 + 7 + 2 = 666.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2427835597 + ... + 2427840947.

Almost surely, 212991362593472 is an apocalyptic number.

12991362593472 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12991362593472, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20473292135376).

12991362593472 is an abundant number, since it is smaller than the sum of its proper divisors (27955221677280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12991362593472 is an equidigital number, since it uses as much as digits as its factorization.

12991362593472 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8459 (or 8434 counting only the distinct ones).

The product of its digits is 44089920, while the sum is 63.

The spelling of 12991362593472 in words is "twelve trillion, nine hundred ninety-one billion, three hundred sixty-two million, five hundred ninety-three thousand, four hundred seventy-two".