130000040143 has 4 divisors (see below), whose sum is σ = 130219265088. Its totient is φ = 129780815200.

The previous prime is 130000040141. The next prime is 130000040227. The reversal of 130000040143 is 341040000031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341040000031 = 31963 ⋅10669837.

It is a cyclic number.

It is not a de Polignac number, because 130000040143 - 2¹ = 130000040141 is a prime.

It is a super-2 number, since 2×130000040143² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130000040141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109611583 + ... + 109612768.

It is an arithmetic number, because the mean of its divisors is an integer number (32554816272).

Almost surely, 2^130000040143 is an apocalyptic number.

130000040143 is a deficient number, since it is larger than the sum of its proper divisors (219224945).

130000040143 is an equidigital number, since it uses as much as digits as its factorization.

130000040143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 219224944.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 130000040143 its reverse (341040000031), we get a palindrome (471040040174).

The spelling of 130000040143 in words is "one hundred thirty billion, forty thousand, one hundred forty-three".