Base | Representation |
---|---|
bin | 111100100010010100… |
… | …0010110010001000111 |
3 | 110102112221202221011011 |
4 | 1321010220112101013 |
5 | 4112220103242120 |
6 | 135415452423051 |
7 | 12251350364131 |
oct | 1710450262107 |
9 | 412487687134 |
10 | 130000446535 |
11 | 50150954673 |
12 | 21240a77a87 |
13 | c349cccb5b |
14 | 6413584051 |
15 | 35ace00c5a |
hex | 1e44a16447 |
130000446535 has 16 divisors (see below), whose sum is σ = 164235915360. Its totient is φ = 98511759360.
The previous prime is 130000446517. The next prime is 130000446617. The reversal of 130000446535 is 535644000031.
It is not a de Polignac number, because 130000446535 - 25 = 130000446503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130000446497 and 130000446506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 549879 + ... + 749911.
It is an arithmetic number, because the mean of its divisors is an integer number (10264744710).
Almost surely, 2130000446535 is an apocalyptic number.
130000446535 is a deficient number, since it is larger than the sum of its proper divisors (34235468825).
130000446535 is a wasteful number, since it uses less digits than its factorization.
130000446535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206898.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 130000446535 its reverse (535644000031), we get a palindrome (665644446566).
The spelling of 130000446535 in words is "one hundred thirty billion, four hundred forty-six thousand, five hundred thirty-five".
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