13000101243303 has 8 divisors (see below), whose sum is σ = 17333498070000. Its totient is φ = 8666719289408.

The previous prime is 13000101243289. The next prime is 13000101243329. The reversal of 13000101243303 is 30334210100031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000101243303 - 2¹³ = 13000101235111 is a prime.

It is a super-2 number, since 2×13000101243303² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13000101243303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000101243343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1487478 + ... + 5311571.

It is an arithmetic number, because the mean of its divisors is an integer number (2166687258750).

Almost surely, 2^{13000101243303} is an apocalyptic number.

13000101243303 is a deficient number, since it is larger than the sum of its proper divisors (4333396826697).

13000101243303 is an equidigital number, since it uses as much as digits as its factorization.

13000101243303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7436401.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13000101243303 its reverse (30334210100031), we get a palindrome (43334311343334).

The spelling of 13000101243303 in words is "thirteen trillion, one hundred one million, two hundred forty-three thousand, three hundred three".