13000102121343 has 4 divisors (see below), whose sum is σ = 17333469495128. Its totient is φ = 8666734747560.

The previous prime is 13000102121317. The next prime is 13000102121389. The reversal of 13000102121343 is 34312120100031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13000102121343 - 2⁴¹ = 10801078865791 is a prime.

It is a super-2 number, since 2×13000102121343² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000102121443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166683686888 + ... + 2166683686893.

It is an arithmetic number, because the mean of its divisors is an integer number (4333367373782).

Almost surely, 2^{13000102121343} is an apocalyptic number.

13000102121343 is a deficient number, since it is larger than the sum of its proper divisors (4333367373785).

13000102121343 is an equidigital number, since it uses as much as digits as its factorization.

13000102121343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4333367373784.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13000102121343 its reverse (34312120100031), we get a palindrome (47312222221374).

The spelling of 13000102121343 in words is "thirteen trillion, one hundred two million, one hundred twenty-one thousand, three hundred forty-three".