1300012102113 has 16 divisors (see below), whose sum is σ = 1766006625600. Its totient is φ = 850486316864.

The previous prime is 1300012102087. The next prime is 1300012102117. The reversal of 1300012102113 is 3112012100031.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 1300012102113 - 2¹⁸ = 1300011839969 is a prime.

It is a super-2 number, since 2×1300012102113² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1300012102092 and 1300012102101.

It is not an unprimeable number, because it can be changed into a prime (1300012102117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17482806 + ... + 17557007.

It is an arithmetic number, because the mean of its divisors is an integer number (110375414100).

Almost surely, 2^{1300012102113} is an apocalyptic number.

It is an amenable number.

1300012102113 is a deficient number, since it is larger than the sum of its proper divisors (465994523487).

1300012102113 is a wasteful number, since it uses less digits than its factorization.

1300012102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35040048.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1300012102113 its reverse (3112012100031), we get a palindrome (4412024202144).

The spelling of 1300012102113 in words is "one trillion, three hundred billion, twelve million, one hundred two thousand, one hundred thirteen".