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130001213100 = 22352113710310337
BaseRepresentation
bin111100100010010101…
…1010001011010101100
3110102120000012212200110
41321010223101122230
54112220302304400
6135415521100020
712251360036043
oct1710453213254
9412500185613
10130001213100
11501513285a0
1221241187610
13c34a20aa45
14641370355a
1535ad002e50
hex1e44ad16ac

130001213100 has 288 divisors, whose sum is σ = 425553762816. Its totient is φ = 30363033600.

The previous prime is 130001213099. The next prime is 130001213101. The reversal of 130001213100 is 1312100031.

It is an interprime number because it is at equal distance from previous prime (130001213099) and next prime (130001213101).

It is a super-2 number, since 2×1300012131002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (130001213101) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 12571132 + ... + 12581468.

It is an arithmetic number, because the mean of its divisors is an integer number (1477617232).

Almost surely, 2130001213100 is an apocalyptic number.

130001213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130001213100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (212776881408).

130001213100 is an abundant number, since it is smaller than the sum of its proper divisors (295552549716).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130001213100 is a wasteful number, since it uses less digits than its factorization.

130001213100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10505 (or 10498 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 130001213100 its reverse (1312100031), we get a palindrome (131313313131).

The spelling of 130001213100 in words is "one hundred thirty billion, one million, two hundred thirteen thousand, one hundred".