130001213131 has 4 divisors (see below), whose sum is σ = 130241511664. Its totient is φ = 129760914600.

The previous prime is 130001213101. The next prime is 130001213141. The reversal of 130001213131 is 131312100031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131312100031 = 7 ⋅18758871433.

It is a cyclic number.

It is not a de Polignac number, because 130001213131 - 2⁵ = 130001213099 is a prime.

It is a super-2 number, since 2×130001213131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130001213101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120148455 + ... + 120149536.

It is an arithmetic number, because the mean of its divisors is an integer number (32560377916).

Almost surely, 2^130001213131 is an apocalyptic number.

130001213131 is a deficient number, since it is larger than the sum of its proper divisors (240298533).

130001213131 is an equidigital number, since it uses as much as digits as its factorization.

130001213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240298532.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130001213131 its reverse (131312100031), we get a palindrome (261313313162).

The spelling of 130001213131 in words is "one hundred thirty billion, one million, two hundred thirteen thousand, one hundred thirty-one".