130001213141 has 2 divisors, whose sum is σ = 130001213142. Its totient is φ = 130001213140.

The previous prime is 130001213101. The next prime is 130001213149. The reversal of 130001213141 is 141312100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66733872241 + 63267340900 = 258329^2 + 251530^2 .

It is a cyclic number.

It is not a de Polignac number, because 130001213141 - 2¹⁸ = 130000950997 is a prime.

It is a super-2 number, since 2×130001213141² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130001213149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000606570 + 65000606571.

It is an arithmetic number, because the mean of its divisors is an integer number (65000606571).

Almost surely, 2^130001213141 is an apocalyptic number.

It is an amenable number.

130001213141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001213141 is an equidigital number, since it uses as much as digits as its factorization.

130001213141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 130001213141 its reverse (141312100031), we get a palindrome (271313313172).

The spelling of 130001213141 in words is "one hundred thirty billion, one million, two hundred thirteen thousand, one hundred forty-one".