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13000122132103 = 373433102346243
BaseRepresentation
bin1011110100101101001110…
…1010010110011010000111
31201000210120212022111000201
42331023103222112122013
53200443222231211403
643352101302151331
72511141100612561
oct275132352263207
951023525274021
1013000122132103
114162359038417
12155b616722547
13733ba207a932
1432d2d0338331
1517826a25e21d
hexbd2d3a96687

13000122132103 has 8 divisors (see below), whose sum is σ = 13355366072048. Its totient is φ = 12645082891584.

The previous prime is 13000122131999. The next prime is 13000122132121. The reversal of 13000122132103 is 30123122100031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000122132103 - 241 = 10801098876551 is a prime.

It is a super-3 number, since 3×130001221321033 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000122130103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51046101 + ... + 51300142.

It is an arithmetic number, because the mean of its divisors is an integer number (1669420759006).

Almost surely, 213000122132103 is an apocalyptic number.

13000122132103 is a deficient number, since it is larger than the sum of its proper divisors (355243939945).

13000122132103 is a wasteful number, since it uses less digits than its factorization.

13000122132103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102349713.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13000122132103 its reverse (30123122100031), we get a palindrome (43123244232134).

The spelling of 13000122132103 in words is "thirteen trillion, one hundred twenty-two million, one hundred thirty-two thousand, one hundred three".

Divisors: 1 37 3433 127021 102346243 3786810991 351354652219 13000122132103