130001230234021 has 4 divisors (see below), whose sum is σ = 133024514658112. Its totient is φ = 126977945809932.

The previous prime is 130001230234019. The next prime is 130001230234147. The reversal of 130001230234021 is 120432032100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130001230234021 - 2¹ = 130001230234019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130001230233983 and 130001230234001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001230234621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1511642211981 + ... + 1511642212066.

It is an arithmetic number, because the mean of its divisors is an integer number (33256128664528).

Almost surely, 2^{130001230234021} is an apocalyptic number.

It is an amenable number.

130001230234021 is a deficient number, since it is larger than the sum of its proper divisors (3023284424091).

130001230234021 is an equidigital number, since it uses as much as digits as its factorization.

130001230234021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3023284424090.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 130001230234021 its reverse (120432032100031), we get a palindrome (250433262334052).

The spelling of 130001230234021 in words is "one hundred thirty trillion, one billion, two hundred thirty million, two hundred thirty-four thousand, twenty-one".