13000123301122 has 4 divisors (see below), whose sum is σ = 19500184951686. Its totient is φ = 6500061650560.

The previous prime is 13000123301107. The next prime is 13000123301149. The reversal of 13000123301122 is 22110332100031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8021419148521 + 4978704152601 = 2832211^2 + 2231301^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13000123301122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250030825279 + ... + 3250030825282.

Almost surely, 2^{13000123301122} is an apocalyptic number.

13000123301122 is a deficient number, since it is larger than the sum of its proper divisors (6500061650564).

13000123301122 is an equidigital number, since it uses as much as digits as its factorization.

13000123301122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6500061650563.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13000123301122 its reverse (22110332100031), we get a palindrome (35110455401153).

The spelling of 13000123301122 in words is "thirteen trillion, one hundred twenty-three million, three hundred one thousand, one hundred twenty-two".