Base | Representation |
---|---|
bin | 11000001101101111… |
… | …00110011100001010 |
3 | 1020120000001120021012 |
4 | 30012313212130022 |
5 | 203111013444204 |
6 | 5545554043522 |
7 | 640104241262 |
oct | 140667463412 |
9 | 36500046235 |
10 | 13000140554 |
11 | 5571271015 |
12 | 26298795a2 |
13 | 12c242097b |
14 | 8b47a47a2 |
15 | 51147d76e |
hex | 306de670a |
13000140554 has 16 divisors (see below), whose sum is σ = 19570063968. Its totient is φ = 6476812752.
The previous prime is 13000140521. The next prime is 13000140577. The reversal of 13000140554 is 45504100031.
13000140554 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1130357 + ... + 1141799.
It is an arithmetic number, because the mean of its divisors is an integer number (1223128998).
Almost surely, 213000140554 is an apocalyptic number.
13000140554 is a deficient number, since it is larger than the sum of its proper divisors (6569923414).
13000140554 is a wasteful number, since it uses less digits than its factorization.
13000140554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13429.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 13000140554 its reverse (45504100031), we get a palindrome (58504240585).
The spelling of 13000140554 in words is "thirteen billion, one hundred forty thousand, five hundred fifty-four".
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