130002002041215 has 16 divisors (see below), whose sum is σ = 209843939580768. Its totient is φ = 68720822317056.

The previous prime is 130002002041211. The next prime is 130002002041217. The reversal of 130002002041215 is 512140200200031.

It is not a de Polignac number, because 130002002041215 - 2² = 130002002041211 is a prime.

It is a super-3 number, since 3×130002002041215³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130002002041191 and 130002002041200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002002041211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38348671474 + ... + 38348674863.

It is an arithmetic number, because the mean of its divisors is an integer number (13115246223798).

Almost surely, 2^{130002002041215} is an apocalyptic number.

130002002041215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130002002041215 is a deficient number, since it is larger than the sum of its proper divisors (79841937539553).

130002002041215 is a wasteful number, since it uses less digits than its factorization.

130002002041215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76697346458.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 130002002041215 its reverse (512140200200031), we get a palindrome (642142202241246).

The spelling of 130002002041215 in words is "one hundred thirty trillion, two billion, two million, forty-one thousand, two hundred fifteen".