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130002005531225 = 525200080221249
BaseRepresentation
bin11101100011110001110011…
…010111000001101001011001
3122001022001220021202211102002
4131203301303113001221121
5114014423101403444400
61140254032531250345
736245222613351332
oct3543616327015131
9561261807684362
10130002005531225
11384715a4a82553
12126b73147499b5
1357701a0c18059
1424161b8697289
1510069b569eed5
hex763c735c1a59

130002005531225 has 6 divisors (see below), whose sum is σ = 161202486858750. Its totient is φ = 104001604424960.

The previous prime is 130002005531171. The next prime is 130002005531239. The reversal of 130002005531225 is 522135500200031.

It can be written as a sum of positive squares in 3 ways, for example, as 2718162496 + 129999287368729 = 52136^2 + 11401723^2 .

It is not a de Polignac number, because 130002005531225 - 224 = 130001988754009 is a prime.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2600040110600 + ... + 2600040110649.

It is an arithmetic number, because the mean of its divisors is an integer number (26867081143125).

Almost surely, 2130002005531225 is an apocalyptic number.

It is an amenable number.

130002005531225 is a deficient number, since it is larger than the sum of its proper divisors (31200481327525).

130002005531225 is an equidigital number, since it uses as much as digits as its factorization.

130002005531225 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5200080221259 (or 5200080221254 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 130002005531225 its reverse (522135500200031), we get a palindrome (652137505731256).

The spelling of 130002005531225 in words is "one hundred thirty trillion, two billion, five million, five hundred thirty-one thousand, two hundred twenty-five".

Divisors: 1 5 25 5200080221249 26000401106245 130002005531225