Base | Representation |
---|---|
bin | 11000001101101111… |
… | …10101010010111101 |
3 | 1020120000011122201221 |
4 | 30012313311102331 |
5 | 203111022421110 |
6 | 5545555233341 |
7 | 640104613552 |
oct | 140667652275 |
9 | 36500148657 |
10 | 13000201405 |
11 | 5571302804 |
12 | 26298a8851 |
13 | 12c2442589 |
14 | 8b47bca29 |
15 | 5114917da |
hex | 306df54bd |
13000201405 has 4 divisors (see below), whose sum is σ = 15600241692. Its totient is φ = 10400161120.
The previous prime is 13000201387. The next prime is 13000201411. The reversal of 13000201405 is 50410200031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 50410200031 = 1621 ⋅31098211.
It can be written as a sum of positive squares in 2 ways, for example, as 3772293561 + 9227907844 = 61419^2 + 96062^2 .
It is not a de Polignac number, because 13000201405 - 25 = 13000201373 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1300020136 + ... + 1300020145.
It is an arithmetic number, because the mean of its divisors is an integer number (3900060423).
Almost surely, 213000201405 is an apocalyptic number.
It is an amenable number.
13000201405 is a deficient number, since it is larger than the sum of its proper divisors (2600040287).
13000201405 is an equidigital number, since it uses as much as digits as its factorization.
13000201405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2600040286.
The product of its (nonzero) digits is 120, while the sum is 16.
Adding to 13000201405 its reverse (50410200031), we get a palindrome (63410401436).
The spelling of 13000201405 in words is "thirteen billion, two hundred one thousand, four hundred five".
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