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13000202111122 = 229435212591063
BaseRepresentation
bin1011110100101101100001…
…1011011100100010010010
31201000210210102210211121121
42331023120123130202102
53200443403220023442
643352113240312454
72511143061460552
oct275133033344222
951023712724547
1013000202111122
11416239a1a4886
12155b63947272a
13733bb58015b5
1432d2dabd7162
151782722ab967
hexbd2d86dc892

13000202111122 has 16 divisors (see below), whose sum is σ = 20641860613440. Its totient is φ = 6130007088912.

The previous prime is 13000202111107. The next prime is 13000202111123. The reversal of 13000202111122 is 22111120200031.

13000202111122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13000202111096 and 13000202111105.

It is not an unprimeable number, because it can be changed into a prime (13000202111123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2606293038 + ... + 2606298025.

It is an arithmetic number, because the mean of its divisors is an integer number (1290116288340).

Almost surely, 213000202111122 is an apocalyptic number.

13000202111122 is a deficient number, since it is larger than the sum of its proper divisors (7641658502318).

13000202111122 is a wasteful number, since it uses less digits than its factorization.

13000202111122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5212591137.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13000202111122 its reverse (22111120200031), we get a palindrome (35111322311153).

The spelling of 13000202111122 in words is "thirteen trillion, two hundred two million, one hundred eleven thousand, one hundred twenty-two".

Divisors: 1 2 29 43 58 86 1247 2494 5212591063 10425182126 151165140827 224141415709 302330281654 448282831418 6500101055561 13000202111122