13000203442 has 4 divisors (see below), whose sum is σ = 19500305166. Its totient is φ = 6500101720.

The previous prime is 13000203407. The next prime is 13000203443. The reversal of 13000203442 is 24430200031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12986653681 + 13549761 = 113959^2 + 3681^2 .

It is not an unprimeable number, because it can be changed into a prime (13000203443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250050859 + ... + 3250050862.

Almost surely, 2^13000203442 is an apocalyptic number.

13000203442 is a deficient number, since it is larger than the sum of its proper divisors (6500101724).

13000203442 is an equidigital number, since it uses as much as digits as its factorization.

13000203442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6500101723.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 13000203442 its reverse (24430200031), we get a palindrome (37430403473).

The spelling of 13000203442 in words is "thirteen billion, two hundred three thousand, four hundred forty-two".