1300020441 has 4 divisors (see below), whose sum is σ = 1733360592. Its totient is φ = 866680292.

The previous prime is 1300020431. The next prime is 1300020473. The reversal of 1300020441 is 1440200031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300020441 - 2⁶ = 1300020377 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300020441.

It is not an unprimeable number, because it can be changed into a prime (1300020431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216670071 + ... + 216670076.

It is an arithmetic number, because the mean of its divisors is an integer number (433340148).

Almost surely, 2^1300020441 is an apocalyptic number.

It is an amenable number.

1300020441 is a deficient number, since it is larger than the sum of its proper divisors (433340151).

1300020441 is an equidigital number, since it uses as much as digits as its factorization.

1300020441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433340150.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 1300020441 is about 36055.7962191934. The cubic root of 1300020441 is about 1091.3986033291.

Adding to 1300020441 its reverse (1440200031), we get a palindrome (2740220472).

The spelling of 1300020441 in words is "one billion, three hundred million, twenty thousand, four hundred forty-one".