130002054423151 has 4 divisors (see below), whose sum is σ = 130002084858600. Its totient is φ = 130002023987704.

The previous prime is 130002054423107. The next prime is 130002054423161. The reversal of 130002054423151 is 151324450200031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130002054423151 - 2¹¹ = 130002054421103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002054423161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7508956 + ... + 17787313.

It is an arithmetic number, because the mean of its divisors is an integer number (32500521214650).

Almost surely, 2^{130002054423151} is an apocalyptic number.

130002054423151 is a deficient number, since it is larger than the sum of its proper divisors (30435449).

130002054423151 is an equidigital number, since it uses as much as digits as its factorization.

130002054423151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30435448.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 130002054423151 in words is "one hundred thirty trillion, two billion, fifty-four million, four hundred twenty-three thousand, one hundred fifty-one".