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13000214220143 = 163318492504189
BaseRepresentation
bin1011110100101101100100…
…1001101000110101101111
31201000210211021121001001212
42331023121021220311233
53200443414320021033
643352114352025035
72511143266423043
oct275133111506557
951023737531055
1013000214220143
1141623a6015537
12155b64153217b
13733bb81810b7
1432d2dc66a023
1517827339e748
hexbd2d9268d6f

13000214220143 has 8 divisors (see below), whose sum is σ = 13080386046000. Its totient is φ = 12920047466688.

The previous prime is 13000214220139. The next prime is 13000214220157. The reversal of 13000214220143 is 34102241200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000214220143 - 22 = 13000214220139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000214220193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3939293 + ... + 6443481.

It is an arithmetic number, because the mean of its divisors is an integer number (1635048255750).

Almost surely, 213000214220143 is an apocalyptic number.

13000214220143 is a deficient number, since it is larger than the sum of its proper divisors (80171825857).

13000214220143 is a wasteful number, since it uses less digits than its factorization.

13000214220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2536201.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13000214220143 its reverse (34102241200031), we get a palindrome (47102455420174).

The spelling of 13000214220143 in words is "thirteen trillion, two hundred fourteen million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 163 31849 2504189 5191387 408182807 79755915461 13000214220143