Base | Representation |
---|---|
bin | 1011110100101101100100… |
… | …1001101000110101101111 |
3 | 1201000210211021121001001212 |
4 | 2331023121021220311233 |
5 | 3200443414320021033 |
6 | 43352114352025035 |
7 | 2511143266423043 |
oct | 275133111506557 |
9 | 51023737531055 |
10 | 13000214220143 |
11 | 41623a6015537 |
12 | 155b64153217b |
13 | 733bb81810b7 |
14 | 32d2dc66a023 |
15 | 17827339e748 |
hex | bd2d9268d6f |
13000214220143 has 8 divisors (see below), whose sum is σ = 13080386046000. Its totient is φ = 12920047466688.
The previous prime is 13000214220139. The next prime is 13000214220157. The reversal of 13000214220143 is 34102241200031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13000214220143 - 22 = 13000214220139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000214220193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3939293 + ... + 6443481.
It is an arithmetic number, because the mean of its divisors is an integer number (1635048255750).
Almost surely, 213000214220143 is an apocalyptic number.
13000214220143 is a deficient number, since it is larger than the sum of its proper divisors (80171825857).
13000214220143 is a wasteful number, since it uses less digits than its factorization.
13000214220143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2536201.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13000214220143 its reverse (34102241200031), we get a palindrome (47102455420174).
The spelling of 13000214220143 in words is "thirteen trillion, two hundred fourteen million, two hundred twenty thousand, one hundred forty-three".
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