Base | Representation |
---|---|
bin | 1011110100101101100110… |
… | …0100010001011101000001 |
3 | 1201000210211202201202201002 |
4 | 2331023121210101131001 |
5 | 3200443423111432431 |
6 | 43352115201421345 |
7 | 2511143412653030 |
oct | 275133144213501 |
9 | 51023752652632 |
10 | 13000221202241 |
11 | 41623a9a54269 |
12 | 155b64393a855 |
13 | 733bb9757110 |
14 | 32d2dd566717 |
15 | 178273ccd3cb |
hex | bd2d9911741 |
13000221202241 has 24 divisors (see below), whose sum is σ = 16886713967424. Its totient is φ = 9744526683360.
The previous prime is 13000221202237. The next prime is 13000221202249. The reversal of 13000221202241 is 14220212200031.
It is not a de Polignac number, because 13000221202241 - 22 = 13000221202237 is a prime.
It is a super-3 number, since 3×130002212022413 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13000221202249) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 197833595 + ... + 197899296.
It is an arithmetic number, because the mean of its divisors is an integer number (703613081976).
Almost surely, 213000221202241 is an apocalyptic number.
It is an amenable number.
13000221202241 is a deficient number, since it is larger than the sum of its proper divisors (3886492765183).
13000221202241 is a wasteful number, since it uses less digits than its factorization.
13000221202241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 395732949 (or 395732930 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13000221202241 its reverse (14220212200031), we get a palindrome (27220433402272).
The spelling of 13000221202241 in words is "thirteen trillion, two hundred twenty-one million, two hundred two thousand, two hundred forty-one".
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