13000231300111 has 8 divisors (see below), whose sum is σ = 14189850054144. Its totient is φ = 11811909136920.

The previous prime is 13000231300099. The next prime is 13000231300151. The reversal of 13000231300111 is 11100313200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000231300111 - 2⁵ = 13000231300079 is a prime.

It is a super-2 number, since 2×13000231300111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000231300151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 324126741 + ... + 324166846.

It is an arithmetic number, because the mean of its divisors is an integer number (1773731256768).

Almost surely, 2^{13000231300111} is an apocalyptic number.

13000231300111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13000231300111 is a deficient number, since it is larger than the sum of its proper divisors (1189618754033).

13000231300111 is a wasteful number, since it uses less digits than its factorization.

13000231300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 648295421.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13000231300111 its reverse (11100313200031), we get a palindrome (24100544500142).

The spelling of 13000231300111 in words is "thirteen trillion, two hundred thirty-one million, three hundred thousand, one hundred eleven".