1300023213231 has 4 divisors (see below), whose sum is σ = 1733364284312. Its totient is φ = 866682142152.

The previous prime is 1300023213221. The next prime is 1300023213253. The reversal of 1300023213231 is 1323123200031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1300023213231 - 2¹⁷ = 1300023082159 is a prime.

It is a super-2 number, since 2×1300023213231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300023213198 and 1300023213207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300023213211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216670535536 + ... + 216670535541.

It is an arithmetic number, because the mean of its divisors is an integer number (433341071078).

Almost surely, 2^{1300023213231} is an apocalyptic number.

1300023213231 is a deficient number, since it is larger than the sum of its proper divisors (433341071081).

1300023213231 is an equidigital number, since it uses as much as digits as its factorization.

1300023213231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433341071080.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 1300023213231 its reverse (1323123200031), we get a palindrome (2623146413262).

The spelling of 1300023213231 in words is "one trillion, three hundred billion, twenty-three million, two hundred thirteen thousand, two hundred thirty-one".