Base | Representation |
---|---|
bin | 11000001101101111… |
… | …11100110011000101 |
3 | 1020120000020012220000 |
4 | 30012313330303011 |
5 | 203111024412013 |
6 | 5550000031513 |
7 | 640105102260 |
oct | 140667746305 |
9 | 36500205800 |
10 | 13000232133 |
11 | 55713238a9 |
12 | 2629902599 |
13 | 12c2453565 |
14 | 8b47c9cd7 |
15 | 51149a973 |
hex | 306dfccc5 |
13000232133 has 40 divisors (see below), whose sum is σ = 22247776320. Its totient is φ = 7410839040.
The previous prime is 13000232107. The next prime is 13000232159. The reversal of 13000232133 is 33123200031.
13000232133 is a `hidden beast` number, since 1 + 300 + 0 + 232 + 133 = 666.
It is an interprime number because it is at equal distance from previous prime (13000232107) and next prime (13000232159).
It is not a de Polignac number, because 13000232133 - 213 = 13000223941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000232173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 210213 + ... + 264933.
It is an arithmetic number, because the mean of its divisors is an integer number (556194408).
Almost surely, 213000232133 is an apocalyptic number.
It is an amenable number.
13000232133 is a deficient number, since it is larger than the sum of its proper divisors (9247544187).
13000232133 is an equidigital number, since it uses as much as digits as its factorization.
13000232133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55159 (or 55150 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 13000232133 its reverse (33123200031), we get a palindrome (46123432164).
The spelling of 13000232133 in words is "thirteen billion, two hundred thirty-two thousand, one hundred thirty-three".
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