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130002553105 = 526000510621
BaseRepresentation
bin111100100010011000…
…0011000100100010001
3110102120002201221211021
41321010300120210101
54112221123144410
6135420005515441
712251404316545
oct1710460304421
9412502657737
10130002553105
1150152063337
1221241712b81
13c34a589949
146413971a25
1535ad1b9eda
hex1e44c18911

130002553105 has 4 divisors (see below), whose sum is σ = 156003063732. Its totient is φ = 104002042480.

The previous prime is 130002553099. The next prime is 130002553147. The reversal of 130002553105 is 501355200031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20165988049 + 109836565056 = 142007^2 + 331416^2 .

It is not a de Polignac number, because 130002553105 - 221 = 130000455953 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130002553105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13000255306 + ... + 13000255315.

It is an arithmetic number, because the mean of its divisors is an integer number (39000765933).

Almost surely, 2130002553105 is an apocalyptic number.

It is an amenable number.

130002553105 is a deficient number, since it is larger than the sum of its proper divisors (26000510627).

130002553105 is an equidigital number, since it uses as much as digits as its factorization.

130002553105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26000510626.

The product of its (nonzero) digits is 2250, while the sum is 25.

Adding to 130002553105 its reverse (501355200031), we get a palindrome (631357753136).

The spelling of 130002553105 in words is "one hundred thirty billion, two million, five hundred fifty-three thousand, one hundred five".

Divisors: 1 5 26000510621 130002553105