13000300012031 has 4 divisors (see below), whose sum is σ = 13000917360600. Its totient is φ = 12999682663464.

The previous prime is 13000300011997. The next prime is 13000300012043. The reversal of 13000300012031 is 13021000300031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000300012031 - 2³⁰ = 12999226270207 is a prime.

It is a super-2 number, since 2×13000300012031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000300011997 and 13000300012015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000300012331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308642696 + ... + 308684813.

It is an arithmetic number, because the mean of its divisors is an integer number (3250229340150).

Almost surely, 2^{13000300012031} is an apocalyptic number.

13000300012031 is a deficient number, since it is larger than the sum of its proper divisors (617348569).

13000300012031 is an equidigital number, since it uses as much as digits as its factorization.

13000300012031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 617348568.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13000300012031 its reverse (13021000300031), we get a palindrome (26021300312062).

The spelling of 13000300012031 in words is "thirteen trillion, three hundred million, twelve thousand, thirty-one".