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1300030201111 = 10911926882579
BaseRepresentation
bin10010111010101111110…
…101101001110100010111
311121021121100011211100211
4102322233311221310113
5132244430212413421
62433120422550251
7162631650245305
oct22725765516427
94537540154324
101300030201111
1146138117a794
1218bb55598387
139579143cb15
1446cc95ab275
1523c3b8dd9e1
hex12eafd69d17

1300030201111 has 4 divisors (see below), whose sum is σ = 1311957083800. Its totient is φ = 1288103318424.

The previous prime is 1300030201109. The next prime is 1300030201123. The reversal of 1300030201111 is 1111020300031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300030201111 - 21 = 1300030201109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300030201091 and 1300030201100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300030201411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5963441181 + ... + 5963441398.

It is an arithmetic number, because the mean of its divisors is an integer number (327989270950).

Almost surely, 21300030201111 is an apocalyptic number.

1300030201111 is a deficient number, since it is larger than the sum of its proper divisors (11926882689).

1300030201111 is a wasteful number, since it uses less digits than its factorization.

1300030201111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11926882688.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1300030201111 its reverse (1111020300031), we get a palindrome (2411050501142).

The spelling of 1300030201111 in words is "one trillion, three hundred billion, thirty million, two hundred one thousand, one hundred eleven".

Divisors: 1 109 11926882579 1300030201111