Base | Representation |
---|---|
bin | 111100100010011001… |
… | …0011110101010010011 |
3 | 110102120010202212020212 |
4 | 1321010302132222103 |
5 | 4112221243233410 |
6 | 135420025354335 |
7 | 12251412065060 |
oct | 1710462365223 |
9 | 412503685225 |
10 | 130003102355 |
11 | 501523a8a65 |
12 | 212419389ab |
13 | c34a71c949 |
14 | 6413a75c67 |
15 | 35ad277b05 |
hex | 1e44c9ea93 |
130003102355 has 64 divisors (see below), whose sum is σ = 200572277760. Its totient is φ = 78741725184.
The previous prime is 130003102351. The next prime is 130003102363. The reversal of 130003102355 is 553201300031.
It is a cyclic number.
It is not a de Polignac number, because 130003102355 - 22 = 130003102351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130003102355.
It is not an unprimeable number, because it can be changed into a prime (130003102351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1155899 + ... + 1263371.
It is an arithmetic number, because the mean of its divisors is an integer number (3133941840).
Almost surely, 2130003102355 is an apocalyptic number.
130003102355 is a deficient number, since it is larger than the sum of its proper divisors (70569175405).
130003102355 is a wasteful number, since it uses less digits than its factorization.
130003102355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107628.
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 130003102355 its reverse (553201300031), we get a palindrome (683204402386).
The spelling of 130003102355 in words is "one hundred thirty billion, three million, one hundred two thousand, three hundred fifty-five".
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