130003113103 has 4 divisors (see below), whose sum is σ = 130003834248. Its totient is φ = 130002391960.

The previous prime is 130003113091. The next prime is 130003113113. The reversal of 130003113103 is 301311300031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 130003113103 - 2²¹ = 130001015951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130003113113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175773 + ... + 539353.

It is an arithmetic number, because the mean of its divisors is an integer number (32500958562).

Almost surely, 2^130003113103 is an apocalyptic number.

130003113103 is a deficient number, since it is larger than the sum of its proper divisors (721145).

130003113103 is an equidigital number, since it uses as much as digits as its factorization.

130003113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 721144.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 130003113103 its reverse (301311300031), we get a palindrome (431314413134).

The spelling of 130003113103 in words is "one hundred thirty billion, three million, one hundred thirteen thousand, one hundred three".