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1300031310211 = 2395439461549
BaseRepresentation
bin10010111010101111111…
…001111000100110000011
311121021121102021011202121
4102322233321320212003
5132244431003411321
62433120502425111
7162631662544654
oct22725771704603
94537542234677
101300031310211
11461381867aa7
1218bb55a32197
139579173a8aa
1446cc97b952b
1523c3ba5c441
hex12eafe78983

1300031310211 has 4 divisors (see below), whose sum is σ = 1305470772000. Its totient is φ = 1294591848424.

The previous prime is 1300031310199. The next prime is 1300031310247. The reversal of 1300031310211 is 1120131300031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300031310211 - 29 = 1300031309699 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300031311211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2719730536 + ... + 2719731013.

It is an arithmetic number, because the mean of its divisors is an integer number (326367693000).

Almost surely, 21300031310211 is an apocalyptic number.

1300031310211 is a deficient number, since it is larger than the sum of its proper divisors (5439461789).

1300031310211 is an equidigital number, since it uses as much as digits as its factorization.

1300031310211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5439461788.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1300031310211 its reverse (1120131300031), we get a palindrome (2420162610242).

The spelling of 1300031310211 in words is "one trillion, three hundred billion, thirty-one million, three hundred ten thousand, two hundred eleven".

Divisors: 1 239 5439461549 1300031310211