Base | Representation |
---|---|
bin | 10010111010101111111… |
… | …001111000100101110111 |
3 | 11121021121102021011202011 |
4 | 102322233321320211313 |
5 | 132244431003411244 |
6 | 2433120502425051 |
7 | 162631662544636 |
oct | 22725771704567 |
9 | 4537542234664 |
10 | 1300031310199 |
11 | 461381867a96 |
12 | 18bb55a32187 |
13 | 9579173a89b |
14 | 46cc97b951d |
15 | 23c3ba5c434 |
hex | 12eafe78977 |
1300031310199 has 2 divisors, whose sum is σ = 1300031310200. Its totient is φ = 1300031310198.
The previous prime is 1300031310181. The next prime is 1300031310247. The reversal of 1300031310199 is 9910131300031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300031310199 - 237 = 1162592356727 is a prime.
It is a super-2 number, since 2×13000313101992 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1300031310199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300031311199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650015655099 + 650015655100.
It is an arithmetic number, because the mean of its divisors is an integer number (650015655100).
Almost surely, 21300031310199 is an apocalyptic number.
1300031310199 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300031310199 is an equidigital number, since it uses as much as digits as its factorization.
1300031310199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 31.
The spelling of 1300031310199 in words is "one trillion, three hundred billion, thirty-one million, three hundred ten thousand, one hundred ninety-nine".
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