Base | Representation |
---|---|
bin | 111100100010011001… |
… | …0111011111000000101 |
3 | 110102120010222221101221 |
4 | 1321010302323320011 |
5 | 4112221311101041 |
6 | 135420032120341 |
7 | 12251413104001 |
oct | 1710462737005 |
9 | 412503887357 |
10 | 130003222021 |
11 | 5015247a962 |
12 | 212419960b1 |
13 | c34a76225a |
14 | 6413aa7701 |
15 | 35ad29d2d1 |
hex | 1e44cbbe05 |
130003222021 has 4 divisors (see below), whose sum is σ = 132134422444. Its totient is φ = 127872021600.
The previous prime is 130003222009. The next prime is 130003222033. The reversal of 130003222021 is 120222300031.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (130003222009) and next prime (130003222033).
It can be written as a sum of positive squares in 2 ways, for example, as 23642445121 + 106360776900 = 153761^2 + 326130^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130003222021 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130003221986 and 130003222004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130003222051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1065600120 + ... + 1065600241.
It is an arithmetic number, because the mean of its divisors is an integer number (33033605611).
Almost surely, 2130003222021 is an apocalyptic number.
It is an amenable number.
130003222021 is a deficient number, since it is larger than the sum of its proper divisors (2131200423).
130003222021 is an equidigital number, since it uses as much as digits as its factorization.
130003222021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2131200422.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 130003222021 its reverse (120222300031), we get a palindrome (250225522052).
The spelling of 130003222021 in words is "one hundred thirty billion, three million, two hundred twenty-two thousand, twenty-one".
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