130003313232211 has 4 divisors (see below), whose sum is σ = 130015985365800. Its totient is φ = 129990641098624.

The previous prime is 130003313232193. The next prime is 130003313232269. The reversal of 130003313232211 is 112232313300031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130003313232211 - 2¹⁵ = 130003313199443 is a prime.

It is a super-2 number, since 2×130003313232211² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130003313232011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6336051406 + ... + 6336071923.

It is an arithmetic number, because the mean of its divisors is an integer number (32503996341450).

Almost surely, 2^{130003313232211} is an apocalyptic number.

130003313232211 is a deficient number, since it is larger than the sum of its proper divisors (12672133589).

130003313232211 is a wasteful number, since it uses less digits than its factorization.

130003313232211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12672133588.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 130003313232211 its reverse (112232313300031), we get a palindrome (242235626532242).

The spelling of 130003313232211 in words is "one hundred thirty trillion, three billion, three hundred thirteen million, two hundred thirty-two thousand, two hundred eleven".