130003322413 has 4 divisors (see below), whose sum is σ = 136845602560. Its totient is φ = 123161042268.

The previous prime is 130003322401. The next prime is 130003322417. The reversal of 130003322413 is 314223300031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 314223300031 = 39839 ⋅7887329.

It is a cyclic number.

It is not a de Polignac number, because 130003322413 - 2²⁹ = 129466451501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130003322417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421140045 + ... + 3421140082.

It is an arithmetic number, because the mean of its divisors is an integer number (34211400640).

Almost surely, 2^130003322413 is an apocalyptic number.

It is an amenable number.

130003322413 is a deficient number, since it is larger than the sum of its proper divisors (6842280147).

130003322413 is an equidigital number, since it uses as much as digits as its factorization.

130003322413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6842280146.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 130003322413 its reverse (314223300031), we get a palindrome (444226622444).

The spelling of 130003322413 in words is "one hundred thirty billion, three million, three hundred twenty-two thousand, four hundred thirteen".