Base | Representation |
---|---|
bin | 1011110100101110000000… |
… | …1100000101011011000111 |
3 | 1201000211010111210012221211 |
4 | 2331023200030011123013 |
5 | 3200444140032131043 |
6 | 43352134210552251 |
7 | 2511146232205063 |
oct | 275134014053307 |
9 | 51024114705854 |
10 | 13000332302023 |
11 | 4162456737170 |
12 | 155b674b98687 |
13 | 733c06785c31 |
14 | 32d310206aa3 |
15 | 17827d926a9d |
hex | bd2e03056c7 |
13000332302023 has 16 divisors (see below), whose sum is σ = 14186335756032. Its totient is φ = 11815022016000.
The previous prime is 13000332302021. The next prime is 13000332302033. The reversal of 13000332302023 is 32020323300031.
It is a cyclic number.
It is not a de Polignac number, because 13000332302023 - 21 = 13000332302021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13000332301985 and 13000332302003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000332302021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 851300878 + ... + 851316148.
It is an arithmetic number, because the mean of its divisors is an integer number (886645984752).
Almost surely, 213000332302023 is an apocalyptic number.
13000332302023 is a deficient number, since it is larger than the sum of its proper divisors (1186003454009).
13000332302023 is a wasteful number, since it uses less digits than its factorization.
13000332302023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32886.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 13000332302023 its reverse (32020323300031), we get a palindrome (45020655602054).
The spelling of 13000332302023 in words is "thirteen trillion, three hundred thirty-two million, three hundred two thousand, twenty-three".
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