130004143313444 has 6 divisors (see below), whose sum is σ = 227507250798534. Its totient is φ = 65002071656720.

The previous prime is 130004143313441. The next prime is 130004143313503. The reversal of 130004143313444 is 444313341400031.

It can be written as a sum of positive squares in only one way, i.e., 116716951887844 + 13287191425600 = 10803562^2 + 3645160^2 .

It is a super-2 number, since 2×130004143313444² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130004143313441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16250517914177 + ... + 16250517914184.

It is an arithmetic number, because the mean of its divisors is an integer number (37917875133089).

Almost surely, 2^{130004143313444} is an apocalyptic number.

It is an amenable number.

130004143313444 is a deficient number, since it is larger than the sum of its proper divisors (97503107485090).

130004143313444 is a wasteful number, since it uses less digits than its factorization.

130004143313444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32501035828365 (or 32501035828363 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 130004143313444 its reverse (444313341400031), we get a palindrome (574317484713475).

The spelling of 130004143313444 in words is "one hundred thirty trillion, four billion, one hundred forty-three million, three hundred thirteen thousand, four hundred forty-four".