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130004143345 = 553490581673
BaseRepresentation
bin111100100010011011…
…0011100110011110001
3110102120012201202020001
41321010312130303301
54112222030041340
6135420103550001
712251423662036
oct1710466346361
9412505652201
10130004143345
1150152a4a08a
122124215b301
13c34a9c570b
146413c6738d
1535ad3d129a
hex1e44d9ccf1

130004143345 has 8 divisors (see below), whose sum is σ = 158948462376. Its totient is φ = 102040987776.

The previous prime is 130004143319. The next prime is 130004143351. The reversal of 130004143345 is 543341400031.

It can be written as a sum of positive squares in 4 ways, for example, as 2982470544 + 127021672801 = 54612^2 + 356401^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130004143345 - 213 = 130004135153 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 245290572 + ... + 245291101.

It is an arithmetic number, because the mean of its divisors is an integer number (19868557797).

Almost surely, 2130004143345 is an apocalyptic number.

It is an amenable number.

130004143345 is a deficient number, since it is larger than the sum of its proper divisors (28944319031).

130004143345 is an equidigital number, since it uses as much as digits as its factorization.

130004143345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 490581731.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130004143345 its reverse (543341400031), we get a palindrome (673345543376).

The spelling of 130004143345 in words is "one hundred thirty billion, four million, one hundred forty-three thousand, three hundred forty-five".

Divisors: 1 5 53 265 490581673 2452908365 26000828669 130004143345