Base | Representation |
---|---|
bin | 111100100010011011… |
… | …0011100110011110001 |
3 | 110102120012201202020001 |
4 | 1321010312130303301 |
5 | 4112222030041340 |
6 | 135420103550001 |
7 | 12251423662036 |
oct | 1710466346361 |
9 | 412505652201 |
10 | 130004143345 |
11 | 50152a4a08a |
12 | 2124215b301 |
13 | c34a9c570b |
14 | 6413c6738d |
15 | 35ad3d129a |
hex | 1e44d9ccf1 |
130004143345 has 8 divisors (see below), whose sum is σ = 158948462376. Its totient is φ = 102040987776.
The previous prime is 130004143319. The next prime is 130004143351. The reversal of 130004143345 is 543341400031.
It can be written as a sum of positive squares in 4 ways, for example, as 2982470544 + 127021672801 = 54612^2 + 356401^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130004143345 - 213 = 130004135153 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 245290572 + ... + 245291101.
It is an arithmetic number, because the mean of its divisors is an integer number (19868557797).
Almost surely, 2130004143345 is an apocalyptic number.
It is an amenable number.
130004143345 is a deficient number, since it is larger than the sum of its proper divisors (28944319031).
130004143345 is an equidigital number, since it uses as much as digits as its factorization.
130004143345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 490581731.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 130004143345 its reverse (543341400031), we get a palindrome (673345543376).
The spelling of 130004143345 in words is "one hundred thirty billion, four million, one hundred forty-three thousand, three hundred forty-five".
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