1300042132313 has 4 divisors (see below), whose sum is σ = 1300044989748. Its totient is φ = 1300039274880.

The previous prime is 1300042132271. The next prime is 1300042132327. The reversal of 1300042132313 is 3132312400031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1113981035209 + 186061097104 = 1055453^2 + 431348^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300042132313 - 2²⁸ = 1299773696857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300042132373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 577028 + ... + 1712613.

It is an arithmetic number, because the mean of its divisors is an integer number (325011247437).

Almost surely, 2^{1300042132313} is an apocalyptic number.

It is an amenable number.

1300042132313 is a deficient number, since it is larger than the sum of its proper divisors (2857435).

1300042132313 is an equidigital number, since it uses as much as digits as its factorization.

1300042132313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2857434.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1300042132313 its reverse (3132312400031), we get a palindrome (4432354532344).

The spelling of 1300042132313 in words is "one trillion, three hundred billion, forty-two million, one hundred thirty-two thousand, three hundred thirteen".