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1300042132314 = 23216673688719
BaseRepresentation
bin10010111010110000100…
…011001010101101011010
311121021122011121222220020
4102322300203022231122
5132244441241213224
62433121530411310
7162632153540202
oct22726043125532
94537564558806
101300042132314
11461387989892
1218bb59590b36
1395793a596c3
1446ccadd5402
1523c3c998c79
hex12eb08cab5a

1300042132314 has 8 divisors (see below), whose sum is σ = 2600084264640. Its totient is φ = 433347377436.

The previous prime is 1300042132271. The next prime is 1300042132327. The reversal of 1300042132314 is 4132312400031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

1300042132314 is an admirable number.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108336844354 + ... + 108336844365.

It is an arithmetic number, because the mean of its divisors is an integer number (325010533080).

Almost surely, 21300042132314 is an apocalyptic number.

1300042132314 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300042132314 is a wasteful number, since it uses less digits than its factorization.

1300042132314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216673688724.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 1300042132314 its reverse (4132312400031), we get a palindrome (5432354532345).

The spelling of 1300042132314 in words is "one trillion, three hundred billion, forty-two million, one hundred thirty-two thousand, three hundred fourteen".

Divisors: 1 2 3 6 216673688719 433347377438 650021066157 1300042132314