1300044314313 has 32 divisors (see below), whose sum is σ = 1930663454720. Its totient is φ = 864596391120.

The previous prime is 1300044314281. The next prime is 1300044314321. The reversal of 1300044314313 is 3134134400031.

1300044314313 is a `hidden beast` number, since 1 + 30 + 0 + 0 + 4 + 4 + 314 + 313 = 666.

It is not a de Polignac number, because 1300044314313 - 2⁵ = 1300044314281 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300044314713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18946998 + ... + 19015488.

It is an arithmetic number, because the mean of its divisors is an integer number (60333232960).

Almost surely, 2^{1300044314313} is an apocalyptic number.

It is an amenable number.

1300044314313 is a deficient number, since it is larger than the sum of its proper divisors (630619140407).

1300044314313 is an equidigital number, since it uses as much as digits as its factorization.

1300044314313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70194 (or 70188 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1300044314313 its reverse (3134134400031), we get a palindrome (4434178714344).

The spelling of 1300044314313 in words is "one trillion, three hundred billion, forty-four million, three hundred fourteen thousand, three hundred thirteen".