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1300044345 = 3586669623
BaseRepresentation
bin100110101111101…
…0001101000111001
310100121021002120120
41031133101220321
510130302404340
6333000243453
744134123515
oct11537215071
93317232516
101300044345
11607928616
12303470589
13179452212
14c4933145
15791ed4d0
hex4d7d1a39

1300044345 has 8 divisors (see below), whose sum is σ = 2080070976. Its totient is φ = 693356976.

The previous prime is 1300044323. The next prime is 1300044437. The reversal of 1300044345 is 5434400031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1300044345 - 216 = 1299978809 is a prime.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43334797 + ... + 43334826.

It is an arithmetic number, because the mean of its divisors is an integer number (260008872).

Almost surely, 21300044345 is an apocalyptic number.

1300044345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1300044345 is a deficient number, since it is larger than the sum of its proper divisors (780026631).

1300044345 is an equidigital number, since it uses as much as digits as its factorization.

1300044345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86669631.

The product of its (nonzero) digits is 2880, while the sum is 24.

The square root of 1300044345 is about 36056.1277039008. The cubic root of 1300044345 is about 1091.4052926168.

Adding to 1300044345 its reverse (5434400031), we get a palindrome (6734444376).

The spelling of 1300044345 in words is "one billion, three hundred million, forty-four thousand, three hundred forty-five".

Divisors: 1 3 5 15 86669623 260008869 433348115 1300044345