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13000595073 = 34333531691
BaseRepresentation
bin11000001101110010…
…10101011010000001
31020120000220122202020
430012321111122001
5203111123020243
65550011512053
7640111143354
oct140671253201
936500818666
1013000595073
115571551554
122629a58629
1312c254c80b
148b488229b
1551151d283
hex306e55681

13000595073 has 4 divisors (see below), whose sum is σ = 17334126768. Its totient is φ = 8667063380.

The previous prime is 13000595053. The next prime is 13000595143. The reversal of 13000595073 is 37059500031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13000595073 - 218 = 13000332929 is a prime.

It is a super-2 number, since 2×130005950732 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13000595053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166765843 + ... + 2166765848.

It is an arithmetic number, because the mean of its divisors is an integer number (4333531692).

Almost surely, 213000595073 is an apocalyptic number.

It is an amenable number.

13000595073 is a deficient number, since it is larger than the sum of its proper divisors (4333531695).

13000595073 is an equidigital number, since it uses as much as digits as its factorization.

13000595073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4333531694.

The product of its (nonzero) digits is 14175, while the sum is 33.

The spelling of 13000595073 in words is "thirteen billion, five hundred ninety-five thousand, seventy-three".

Divisors: 1 3 4333531691 13000595073