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13000595053 is a prime number
BaseRepresentation
bin11000001101110010…
…10101011001101101
31020120000220122201111
430012321111121231
5203111123020203
65550011512021
7640111143325
oct140671253155
936500818644
1013000595053
115571551536
122629a58611
1312c254c7c4
148b4882285
1551151d26d
hex306e5566d

13000595053 has 2 divisors, whose sum is σ = 13000595054. Its totient is φ = 13000595052.

The previous prime is 13000595051. The next prime is 13000595143. The reversal of 13000595053 is 35059500031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8853492649 + 4147102404 = 94093^2 + 64398^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000595053 - 21 = 13000595051 is a prime.

Together with 13000595051, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000595051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500297526 + 6500297527.

It is an arithmetic number, because the mean of its divisors is an integer number (6500297527).

Almost surely, 213000595053 is an apocalyptic number.

It is an amenable number.

13000595053 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000595053 is an equidigital number, since it uses as much as digits as its factorization.

13000595053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10125, while the sum is 31.

The spelling of 13000595053 in words is "thirteen billion, five hundred ninety-five thousand, fifty-three".