Base | Representation |
---|---|
bin | 11000001101110010… |
… | …11100101111101011 |
3 | 1020120000222011222111 |
4 | 30012321130233223 |
5 | 203111130001011 |
6 | 5550012303151 |
7 | 640111330114 |
oct | 140671345753 |
9 | 36500864874 |
10 | 13000625131 |
11 | 557157209a |
12 | 2629a71ab7 |
13 | 12c25603c0 |
14 | 8b488d20b |
15 | 511527121 |
hex | 306e5cbeb |
13000625131 has 4 divisors (see below), whose sum is σ = 14000673232. Its totient is φ = 12000577032.
The previous prime is 13000625123. The next prime is 13000625147. The reversal of 13000625131 is 13152600031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13000625131 - 23 = 13000625123 is a prime.
It is a super-2 number, since 2×130006251312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13000625171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500024031 + ... + 500024056.
It is an arithmetic number, because the mean of its divisors is an integer number (3500168308).
Almost surely, 213000625131 is an apocalyptic number.
13000625131 is a deficient number, since it is larger than the sum of its proper divisors (1000048101).
13000625131 is a wasteful number, since it uses less digits than its factorization.
13000625131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1000048100.
The product of its (nonzero) digits is 540, while the sum is 22.
The spelling of 13000625131 in words is "thirteen billion, six hundred twenty-five thousand, one hundred thirty-one".
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