13001001113013 has 4 divisors (see below), whose sum is σ = 17334668150688. Its totient is φ = 8667334075340.

The previous prime is 13001001112951. The next prime is 13001001113027. The reversal of 13001001113013 is 31031110010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001001113013 - 2¹³ = 13001001104821 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13001001112983 and 13001001113001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001001113213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166833518833 + ... + 2166833518838.

It is an arithmetic number, because the mean of its divisors is an integer number (4333667037672).

Almost surely, 2^{13001001113013} is an apocalyptic number.

It is an amenable number.

13001001113013 is a deficient number, since it is larger than the sum of its proper divisors (4333667037675).

13001001113013 is an equidigital number, since it uses as much as digits as its factorization.

13001001113013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4333667037674.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 13001001113013 its reverse (31031110010031), we get a palindrome (44032111123044).

The spelling of 13001001113013 in words is "thirteen trillion, one billion, one million, one hundred thirteen thousand, thirteen".