Search a number
-
+
1300100412002 = 27509182444627
BaseRepresentation
bin10010111010110100000…
…001011111001001100010
311121021210020021220121012
4102322310001133021202
5132300101201141002
62433131411500522
7162633462110630
oct22726401371142
94537706256535
101300100412002
11461407875217
1218bb74bb7742
13957a2b53622
1446cd4a46350
1523c42b5bd52
hex12eb405f262

1300100412002 has 16 divisors (see below), whose sum is σ = 2233122246720. Its totient is φ = 556091220048.

The previous prime is 1300100411989. The next prime is 1300100412011. The reversal of 1300100412002 is 2002140010031.

It is a super-2 number, since 2×13001004120022 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 91215188 + ... + 91229439.

It is an arithmetic number, because the mean of its divisors is an integer number (139570140420).

Almost surely, 21300100412002 is an apocalyptic number.

1300100412002 is a deficient number, since it is larger than the sum of its proper divisors (933021834718).

1300100412002 is a wasteful number, since it uses less digits than its factorization.

1300100412002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182445145.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1300100412002 its reverse (2002140010031), we get a palindrome (3302240422033).

The spelling of 1300100412002 in words is "one trillion, three hundred billion, one hundred million, four hundred twelve thousand, two".

Divisors: 1 2 7 14 509 1018 3563 7126 182444627 364889254 1277112389 2554224778 92864315143 185728630286 650050206001 1300100412002