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1300101020131 = 53503241720177
BaseRepresentation
bin10010111010110100000…
…011110011100111100011
311121021210021102210210111
4102322310003303213203
5132300101330121011
62433131432512151
7162633500222614
oct22726403634743
94537707383714
101300101020131
11461408150101
1218bb7524b657
13957a3007374
1446cd4b63c0b
1523c42c2c121
hex12eb40f39e3

1300101020131 has 16 divisors (see below), whose sum is σ = 1327879635264. Its totient is φ = 1272445118464.

The previous prime is 1300101020129. The next prime is 1300101020143. The reversal of 1300101020131 is 1310201010031.

It is a cyclic number.

It is not a de Polignac number, because 1300101020131 - 21 = 1300101020129 is a prime.

It is a super-2 number, since 2×13001010201312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300101023131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64424715 + ... + 64444891.

It is an arithmetic number, because the mean of its divisors is an integer number (82992477204).

Almost surely, 21300101020131 is an apocalyptic number.

1300101020131 is a deficient number, since it is larger than the sum of its proper divisors (27778615133).

1300101020131 is a wasteful number, since it uses less digits than its factorization.

1300101020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23150.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1300101020131 its reverse (1310201010031), we get a palindrome (2610302030162).

The spelling of 1300101020131 in words is "one trillion, three hundred billion, one hundred one million, twenty thousand, one hundred thirty-one".

Divisors: 1 53 503 2417 20177 26659 128101 1069381 1215751 10149031 48767809 64434803 537898643 2584693877 24530207927 1300101020131