13001021413 has 4 divisors (see below), whose sum is σ = 13001256160. Its totient is φ = 13000786668.

The previous prime is 13001021399. The next prime is 13001021441. The reversal of 13001021413 is 31412010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31412010031 = 1367 ⋅22978793.

It is a cyclic number.

It is not a de Polignac number, because 13001021413 - 2³³ = 4411086821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001021713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16918 + ... + 162136.

It is an arithmetic number, because the mean of its divisors is an integer number (3250314040).

Almost surely, 2^13001021413 is an apocalyptic number.

It is an amenable number.

13001021413 is a deficient number, since it is larger than the sum of its proper divisors (234747).

13001021413 is an equidigital number, since it uses as much as digits as its factorization.

13001021413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234746.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13001021413 its reverse (31412010031), we get a palindrome (44413031444).

The spelling of 13001021413 in words is "thirteen billion, one million, twenty-one thousand, four hundred thirteen".