Base | Representation |
---|---|
bin | 10010111010110100001… |
… | …001000100111111011011 |
3 | 11121021210101001000101020 |
4 | 102322310021010333123 |
5 | 132300102203331021 |
6 | 2433131522253523 |
7 | 162633515036460 |
oct | 22726411047733 |
9 | 4537711030336 |
10 | 1300102402011 |
11 | 461408a04356 |
12 | 18bb757b72a3 |
13 | 957a339c34a |
14 | 46cd5003667 |
15 | 23c42e017c6 |
hex | 12eb4244fdb |
1300102402011 has 32 divisors (see below), whose sum is σ = 2101410501120. Its totient is φ = 697959307776.
The previous prime is 1300102401989. The next prime is 1300102402037. The reversal of 1300102402011 is 1102042010031.
It is not a de Polignac number, because 1300102402011 - 27 = 1300102401883 is a prime.
It is a super-3 number, since 3×13001024020113 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1300102402051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3070221 + ... + 3467918.
It is an arithmetic number, because the mean of its divisors is an integer number (65669078160).
Almost surely, 21300102402011 is an apocalyptic number.
1300102402011 is a deficient number, since it is larger than the sum of its proper divisors (801308099109).
1300102402011 is a wasteful number, since it uses less digits than its factorization.
1300102402011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6538723.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1300102402011 its reverse (1102042010031), we get a palindrome (2402144412042).
The spelling of 1300102402011 in words is "one trillion, three hundred billion, one hundred two million, four hundred two thousand, eleven".
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